Question

Please Answer this question ​

Answer 1

It took me 15 minutes to do so, please mark me as brainliest

Assuming question is

sec(4θ+40) = cosec θ

sec(90−(50−4θ)) = cosec θ

cosec(50−4θ) = cosec θ           (Since sec(90−x)=cosec x)

50 − 4θ = θ

5θ = 50

θ = 10°

sin²(2θ+10) + cos²(5θ−20) = sin²(2(10) + 10) + cos²(5(10)−20)

=sin²30 + cos²30 = (1/2)² + (√3/2)²

=1/4 + 3/4 = 4/4 = 1

LHS = RHS (HENCE PROOVED)