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x²+2x-35
x²+7x-5x-35
=x(x+7)-5(x+7)
=(x+7)(x-5)
(x+7)=0
x=-7
(x-5)=0
x=5
So,alpha=-7=€
& beta=5=¥
For second equation,
the roots are
1/€=1/-7
1/¥=1/5
sum of roots=1/€+1/¥
=-1/7+1/5
=(-5+7)/35
=2/35
Product of roots=1/€×/¥
=-1/7×1/5
=-1/35
now,
For forming the quadratic equation we have formula
=>x²-(sum of roots)x+(product of roots)
so,putting value here,
=>x²-(2/35)x+(-1/35)
=>35x²-2x-1
is the required quadratic equation.
@Altaf
x²+7x-5x-35
=x(x+7)-5(x+7)
=(x+7)(x-5)
(x+7)=0
x=-7
(x-5)=0
x=5
So,alpha=-7=€
& beta=5=¥
For second equation,
the roots are
1/€=1/-7
1/¥=1/5
sum of roots=1/€+1/¥
=-1/7+1/5
=(-5+7)/35
=2/35
Product of roots=1/€×/¥
=-1/7×1/5
=-1/35
now,
For forming the quadratic equation we have formula
=>x²-(sum of roots)x+(product of roots)
so,putting value here,
=>x²-(2/35)x+(-1/35)
=>35x²-2x-1
is the required quadratic equation.
@Altaf
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