Question

please answer this question ​

Answer 1

a2b2x2+b2x-1=0
= 2b^2 x^2 2x = 1

Answer 2

$\huge\pink {\boxed{\mathbb{☆AnSwER☆:-}}}$

$\bold{☆\:Given\:Equation\:☆}$

${a}^{2} {b}^{2} {x}^{2} + {b}^{2}x - {a}^{2} x - 1 = 0$

$\bold{☆\:Finding\:the\:value\:of\:x\:☆}$

${b}^{2} x( {a}^{2} x + 1) - ({a}^{2}x + 1) = 0$

$( {b}^{2}x - 1) ( {a}^{2} x + 1) = 0$

$( {b}^{2} x - 1) = 0 \: \: \: and \: \: \: ( {a}^{2} x + 1) = 0$

${b}^{2}x = 1 \: \: and \: \: {a}^{2} x = - 1$

$x = \frac{1}{ {b}^{2} } \: \: and \: \: x = \frac{ - 1}{ {a}^{2} }$

$\huge\mathcal {Hope\:it\:Might\:Help\:You}$