Question

please answer this question

Answer 1

this is your answer of your question

Answer 2

Hi ,

It is given that

<OAB = 30°

∆AOB is a isoseceles triangle ,

Since OA = OB = radius

<OAB = <ABO = 30°

Therefore ,

We know that ,

<AOB + <OAB + <ABO = 180°

< AOB + 30° + 30° = 180°

= 180 - 60

= 120°

2 ) <ABP = 90°

[ Tangent , radius relation ]

<ABP + <ABO = 90°

<ABP = 90 - <ABO

= 90 - 30


= 60°
I hope this helps you

:)