Question

please answer this question ​

Answer 1

Answer :

-1/√b (fourth option)

Solution :

Here ,

The given quadratic equation is ;

(√ab)x² + (√a + √b)x + 1 = 0

Let's find its solutions (roots) by middle term splitting method .

Thus ,

=> (√ab)x² + (√a + √b)x + 1 = 0

=> (√ab)x² + √a·x + √b·x + 1 = 0

=> √a·x(√b·x + 1) + (√b·x + 1) = 0

=> (√b·x + 1)(√a·x + 1) = 0

=> x = -1/√b , -1/√a

Hence ,

-1/√a , -1/√b are the solutions of the given quadratic equation .

Answer 2

Answer:

-1/√b

Step-by-step explanation:

√abx²+(√a+√b)x+1=0

√a√bx²+√ax+√bx+1=0

(√ax+1)(√bx +1)+(√bx+1) = 0

(√ax+1)(√bx+1) = 0

x = -1/√a or -1/√b