Question

please answer this question ​

Answer 1

Step-by-step explanation:

Given

$x + y = 28 \\ xy = 192 \\ {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ {28}^{2} = {x}^{2} + {y}^{2} + 2(192) \\ 784 - 384 = {x}^{2} + {y}^{2} \\ 400 - 384 = {x}^{2} + {y}^{2} - 2xy \\ {(x - y)}^{2} = 16 \\ x - y = \sqrt{16} \\ x - y = 4 \: or \: x - y = - 4 \\ x = 16 \: y = 12 \\ or \: \: x = 12 \: y = 16$

so answer is12,16

Answer 2

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