Physics, asked by Anonymous, 7 months ago

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Answered by Anonymous
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Answer:

\frac{dy}{dx}  = (x {}^{2} - 3) {}^{9}

Now differentation with respect to X

 \frac{dy}{dx}  =  \frac{d(x {}^{2}  - 3) {}^{9} }{dx}

 \frac{dy}{dx}  = 9 \times (x {}^{2} - 3) \frac{d(x {}^{2}  - 3)}{dx}

 \frac{dy}{dx}  = 9 \times (x {}^{2}  - 3)(2x - 0)

 \frac{dy}{dx}  = 9 \times (x {}^{2} - 3)2x

 \frac{dy}{dx}  = 18x(x {}^{2}  - 3)

Additional information :

If the power is present.. We should Differnatatiate power first..

Then,

The dervatative of

x {}^{2}  = 2x

We can find the dervatative by

  \frac{d(x {}^{n)} }{dx}  = nx {}^{n - 1}

General formula

Dervatative of constant will be 0

Example = number

Hope this helps u

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