Question

please answer this question ​

Answer 1

Answér :

No. of terms , n = 43

Note :

★ A.P. (Arithmetic Progression) : A sequence in which the difference between the consecutive terms are equal is said to be in A.P.

★ If a1 , a2 , a3 , . . . , an are in AP , then

a2 - a1 = a3 - a2 = a4 - a3 = . . .

★ The common difference of an AP is given by ; d = a(n) - a(n-1) .

★ The nth term of an AP is given by ;

a(n) = a + (n - 1)d .

Solution :

• Given AP : 6 , 10 , 14 , 18 , . . . , 174 .

• To find : No. of terms , n = ?

Here , we have ;

• First term , a = 6

• Common difference , d = 10 - 6 = 4

• Last term , l = 174 .

We have ;

=> l = 174

=> a + (n - 1)d = 174

=> 6 + (n - 1)4 = 174

=> 4(n - 1) = 174 - 6

=> 4(n - 1) = 168

=> n - 1 = 168/4

=> n - 1 = 42

=> n = 42 + 1

=> n = 43

Hence ,

No. of terms in the given AP is 43 .

Answer 2

I hope this will help you.....