Question

please answer this question ​

Answer 1

Answer:

Given n

th

term of AP is 4n−10

Putting n=1,2,3,4,....., we get

At n=1:4n−10=4×1−10=4−10=−6

At n=2:4n−10=4×2−10=8−10=−2

At n=3:4n−10=4×3−10=12−10=2

At n=1:4n−10=4×4−10=16−10=6

We see that −6,−2,2,6,... are in AP as common difference is same.

Common difference =−2−(−6)=4.

Answer 2

Answer:

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