Question

please answer this question ​

Answer 1

AP=5,15,25..............

Here a=5,d=a2-a1=15-5=10

an=a+(n-1)d

a31=5+(31-1)10

=5+30(10)

=5+300

=305

Let the term be 130 more than the 31st term

an=a+(n-1)d

305+130=5+(n-1)10

435=5+10n-10

435=10n-5

10n-5=435

10n=435+5

10n=440

n=440/10

n=44

The 44th term of AP is 130 more than its 31st term. (This is the required answer.) [If you liked my answer then please mark me as brainliest and I will definitely follow you back.]