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we will find distance covered for 5 and 2 cm dimensional
so = 2 (5+2)
= 2 * 7
= 14cm
then we find distance for 20 and 2 cm dimensional
so = 2 ( 20 + 2 )
= 2* 22
= 22 cm
and we also need 50 cm ribbon to make bow
so total ribbon needed = 50cm + 22cm + 14 cm
= 86 cm
so total 86 cm bow needed
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please..............
we will find distance covered for 5 and 2 cm dimensional
so = 2 (5+2)
= 2 * 7
= 14cm
then we find distance for 20 and 2 cm dimensional
so = 2 ( 20 + 2 )
= 2* 22
= 22 cm
and we also need 50 cm ribbon to make bow
so total ribbon needed = 50cm + 22cm + 14 cm
= 86 cm
so total 86 cm bow needed
please mark me as brainliast
please..............
Anuj3105:
please mark me as brainliast
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