Question

please answer this question ​

Answer 1

Answer:

ok I will answer your questions ok bye

Answer 2

Answer:

Since, the given three numbers ( 2p - 1 ), ( 3p + 1 ) and 11 are in AP, then

c - b = b - a

Therefore,

11 - ( 3p + 1 ) = ( 3p + 1 ) - ( 2p - 1 )

11 - 3p - 1 = 3p + 1 - 2p + 1

10 - 3p = p + 2

8 = 4p

=> p = 2

So, value of p is 2.

Hence, the given numbers will be =>

( 2p - 1 ) = 2 × 2 - 1 = 4 - 1 = 3

( 3p + 1 ) = 3 × 2 + 1 = 6 + 1 = 7

that is => 3, 7, 11