Math, asked by niteshshaw723, 6 months ago

please answer this question ​

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Answered by singhkarishma882
1

\huge\red {\boxed {\mathfrak {AnsWer:-}}}

\sf\orange {\underline {\sf Given:-}}

A.P = 6,10,14,18...,174

{a}{1} = 6

d = {a}{2}-{a}{1}

d = 10-6

d = 4

Last term an = 174

\sf\green {\underline{\sf To\:Find:-}}

{n}^{th} term

\sf\blue {\underline {\sf Now:-}}

{a}{n} = a+(n-1)d

174 = 6+(n-1)4

174 = 6+4n-4

174 = 4n+2

174-2 = 4n

172 = 4n

\frac {172}{4} = n

n= 43

\huge\color{aqua}There\:are\:43\:terms

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