Question

Please answer this question.................

Answer 1

q and X is a linesegment so

x + 136 = 180 degrees

= x = 180 -136
= x = 44 degrees

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Answer 2

x=180°-136° (linear pair)
x=  44°
∠Q= x+25° (given)
we now know x. so:
∠Q=44°+25°
∠Q=69°
∠P+∠Q+∠PRQ=180° (angle sum property)
∠P+69°+44°=180°
∠P+113°=180°
∠P=180°-113°
∠P=  67°


∴all the angles of ΔPQR are:
∠PRQ=44°
∠PQR=69°
∠QPR=67°