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q and X is a linesegment so
x + 136 = 180 degrees
= x = 180 -136
= x = 44 degrees
if it helpful plz mark brainlist and follow me
x + 136 = 180 degrees
= x = 180 -136
= x = 44 degrees
if it helpful plz mark brainlist and follow me
Ash0123:
tks
Answered by
1
x=180°-136° (linear pair)
x= 44°
∠Q= x+25° (given)
we now know x. so:
∠Q=44°+25°
∠Q=69°
∠P+∠Q+∠PRQ=180° (angle sum property)
∠P+69°+44°=180°
∠P+113°=180°
∠P=180°-113°
∠P= 67°
∴all the angles of ΔPQR are:
∠PRQ=44°
∠PQR=69°
∠QPR=67°
x= 44°
∠Q= x+25° (given)
we now know x. so:
∠Q=44°+25°
∠Q=69°
∠P+∠Q+∠PRQ=180° (angle sum property)
∠P+69°+44°=180°
∠P+113°=180°
∠P=180°-113°
∠P= 67°
∴all the angles of ΔPQR are:
∠PRQ=44°
∠PQR=69°
∠QPR=67°
thank u very much............
ur welcome
thanks for marking my answer as the brainliest
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