Question

please answer this question ​

Answer 1

Required answer :

The first 40 positive integers divisible by 6 are 6,12,18,..and so on....(upto 40 terms)

Therefore,

The given series is in A. P.(arithmetic progession) with :

First term a = 6

And also ,

Common difference d = 6

We know that :

$\sf \longrightarrow { \underline{ \boxed{ \sf{ sum \: of \: n \: terms = \frac{n}{2} (2a + (n - 1) d)}}}}$

Where,

n = 6

a = 40

d = 6

Substituting the given values as follows :

$\sf \longrightarrow \frac{ \cancel{40}}{ \cancel 2} \times \{2(6) + (40 - 1)6 \}$

$\sf \longrightarrow \: 20 \{ 12 + 39 \times 6\}$

$\sf \longrightarrow 20 \{12 + 234 \}$

$\sf \longrightarrow 20 \{ 246\}$

$\sf \longrightarrow \bf{4920} \: ans.$

Answer 2

Answer:

sorry my answer is wrong..