Math, asked by niteshshaw723, 7 months ago

please answer this question ​

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Answers

Answered by madhu865
1

Step-by-step explanation:

sum of 15 multiples of 8 is 960

for explanation see the attachment

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Answered by InfiniteSoul
2

\sf{\bold{\green{\underline{\underline{Given}}}}}

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  • First term = a = 8
  • common difference = d = 8
  • No. of times = 15

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\sf{\bold{\green{\underline{\underline{To\:Find}}}}}

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  • Sum of first 15 terms = ??

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\sf{\bold{\green{\underline{\underline{Solution}}}}}

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\sf{\red{\boxed{\bold{S = \dfrac{n}{2} [ 2a + ( n - 1 ) d ] }}}}

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\sf : \implies\: {\bold{ S = \dfrac{15}{2} [ 2\times 8 + ( 15 - 1 ) 8 ] }}

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\sf : \implies\: {\bold{ S = \dfrac{15}{2} [ 2\times 8 + 14 \times 8] }}

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\sf : \implies\: {\bold{ S = \dfrac{15}{2} [ 16 + 14 \times 8] }}

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\sf : \implies\: {\bold{ S = \dfrac{15}{2} [ 16 + 112] }}

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\sf : \implies\: {\bold{ S = \dfrac{15}{2} \times 128 }}

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\sf : \implies\: {\bold{ S = 15 \times 64}}

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\sf : \implies\: {\bold{ S = 960 }}

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\sf{\bold{\green{\underline{\underline{Answer}}}}}

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  • Sum of first 15 multiples of 8 is 960
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