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Answer:
(n*n) = (n^2)
Step-by-step explanation:
Given
S 7 =49 and S 17 =289
By using S n= n/2 * [2a+(n−1)d] we have,
S 7 = 7/2* [2a+(7−1)d]=49
⇒49=7/2 [2a+(7−1)d]
⇒49= 7/2 * (2a+6d)
⇒7=a+3d
⇒a+3d=7...................(i)
S 17 = 17/2 *[2a+(17−1)d]=289
⇒289= 17/2* [2a+(17−1)d]
⇒289= 17/2 *(2a+16d)
⇒17=a+8d
⇒a+8d=17......................(ii)
Substituting (i) from (ii), we get
5d=10 or d=2
From equation (i),
a+3(2)=7
a+6=7 or a=1
S n= n/2*[2(1)+(n−1)2]
= n/2 [2+(n−1)2]
= n/2(2+2n−2)= n^2= ( n*n)
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