Question

please answer this question ​

Answer 1

Answer:

250

Step-by-step explanation:

According to question

a1=3

a2=8

and Common difference of first and second APs are same i.e d1 =d2=d

Therefore,sum of 50 terms for first AP

s1= n/2[2a+(n-1)d]

s1=50/2[2*3+(50-1)d]

s1=25[6+49d].....(1)

Similarly for S2

s2= n/2[2a+(n-1)d]

s2=50/2[2*8+(50-1)d]

s2=25[16+49d].......(2)

Now , difference of s2 and s1

s2-s1=25[16+49d]-25[6+49d]

=25*16+25*49d-25*6-25*49d

=25*16-25*6

=25(16-6)

=25*10

=250

Hope,this will be helpful:)