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1
Answer:
600
Step-by-step explanation:
a16= 5(a3)...............(i)
a10=41..............(ii)
a+15d= 5(a+2d)
a+15d= 5a + 10d
a= 5d/4
Putting the value of a in eq ii
a+9d=41
5d/4+9d=41
d=4
Putting the value of d in eq ii
a+9(4)=41
a+36=41
a=5
Sn=n/2(2a+(n-1)d)
Putting all the values
S15= 15/2(2x5+(15-1)4)
S15=600
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