Question

please answer this question ​

Answer 1

Step-by-step explanation:

given that

first term of an AP=P

Common difference d=a

find its 10th term

we know that

an=a+(n-1)d

a10=p+(10-1)a

a10=p+9q

hence 10th term is p+9q

Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\bf{Answer}}}}}}}$

${\bold{\blue{\boxed{\bf{Given}}}}}$

• first term = a = p
• common diff. = d = q
• no. of times = n = 10

⠀⠀⠀⠀

${\bold{\blue{\boxed{\bf{To\:find}}}}}$

• $\bold{a_{10}}= ???$

${\bold{\blue{\boxed{\bf{ Formulae\:used }}}}}$

$\bold {a_n = a + (n-1)d}$

${\bold{\blue{\boxed{\bf{Solution }}}}}$

$a_{10} = p + (10-1)\times -q$

$a_{10} = p + 9 \times q$

$a_{10} = p + 9q$

${\bold{\blue{\boxed{\boxed{\bf{a_{10} = p + 9q}}}}}}$

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