Math, asked by rozeypandita, 5 months ago

please answer this question​

Attachments:

Answers

Answered by sritarutvik
1

Answer:

34

Step-by-step explanation:

a=1/(3-2v2)=1/(3-2v2) *(3+2v2)/3+2v2)

=(3+2v2)/(3^2-(2v2)^2)

=(3+2v2)/9-8)=3+2v2

a^2=(3+2v2)^2=9+12v2+8=17+12v2

similarly b=1/3+2v2=3-2v2

b^2=(3-2v2)^2=17-12v2

a^2+b^2=17+12v2+17-12v2=34

Similar questions