Question

please answer this question ​

Answer 1

Answer:

0 or option D is the right answer

Step-by-step explanation:

(s-t)(s+t)+(t+p)(t-p)+(p-s)(p+s)

Using (a-b)(a+b) = $a^2-b^2$

$s^2-t^2+t^2-p^2+p^2-s^2$

$\not{{s}^{2}} - \not{{s}^{2}} + \not{ {t}^{2}} - \not{{t}^{2}} + \not{ {p}^{2} } - \not{{p}^{2}} \\ \\ 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

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