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Answer:
2 unit²
Step-by-step explanation:
A(1,-4) is the vertex of ΔABC
AP and AQ are two lines passing through A
B(3/2,-5/2) and C(1/2,-3/2) are the mid points of AP and AQ
Thus we have to find area of ΔABC
area= { 1(-5/2+3/2)+3/2*( -3/2+4) +1/2(-4+5/2) }
= { 1*(-1) +3/2*(5/2)+1/2*(-3/2)}
=(-1+15/4-3/4)
=1/4(-4+15-3)
=8/4=2 unit²
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answer for the given problem is given
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