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in the figure given below find angle abd also find angle abc if angle c = 3 angle abc =2 ( angle a + angle b )
given ,
< c =3 < b = 2 ( < a + < b ).....1
let < a = x
< b = y
< c = 3 < b = 3y
from (1) let as consider first and last term < c = 2 ( < a + < b )
2 < a + 2 < b - < c = 0 .......(a)
as we know that , the sum of interior angle of a triangle is 180 , we have
< a + < b + < c = 180 ......(b)
< c = 120°
< c = 3 < b = < b = < c / 3 = 120/3
< b = 40°
< a + < b + < c = 180°= < a + 40° + 120° =180° = < a + 160° = 180° = < a = 180° - 160°
< A = 20 °
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