please answer this question
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hay!!
dear user -
In the given figure we know that AO=AR
AO=5cm
and, BP=PC
BP=PO=PC=CR
it's same external point
AO=>5. = BP=BQ
AR=5. =CP=CR
then in △ABC= AO+AR=>5+5=>10
I hope it's help you
dear user -
In the given figure we know that AO=AR
AO=5cm
and, BP=PC
BP=PO=PC=CR
it's same external point
AO=>5. = BP=BQ
AR=5. =CP=CR
then in △ABC= AO+AR=>5+5=>10
I hope it's help you
Anonymous:
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thanks dear
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