Question

please answer this question 30th one
help me................​

Answer 1

$in \: triangle \: abc \: \\ we \: know \: \sin(?)$

$in \: triangle \: abc \: \\ we \: know \: \sin(theta) = 5 \div 13 \\ so \: tan(theta) = 5 \div \sqrt{13 {}^{2} - 5 { }^{2} } = 5 \div \sqrt{169 - 25 \\ =5 \div 12$