Math, asked by niteshshaw723, 4 months ago

please answer this question ​

Attachments:

Answers

Answered by negiabhishek236
2

Answer:

Given distribution

Class-interval 0−5 5−10 10−15 15−20 20−25 25−30

Frequency 5 3 9 10 8 5

Now we can prepare a table for calculating median

Class-interval Frequency Cumulative frequency

0−5 5 5

5−10 3 5+3=8

10−15 9 8+9=17(c.l)

15−20 10 17+10=27

20−25 8 27+8=35

25−30 5 35+5=40

N=40

⇒N/2=40/2=20

then the median class;

15−20

Lowest limit(l)=15

Class width(h)=5

Frequency(f)=10

and c.f= preceding cumulative frequency of median class

=median

=l+(

f

N/2−c.f

)×h

=15+(

10

20−17

)×15

=15+

10

3×5

=15+

10

15

Median=15+1.5=16.5.

Step-by-step explanation:

agar nhi dikha to pic m dekh lo

Attachments:
Answered by Anonymous
1

Answer:

Thanks for free points

Similar questions