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Q4. The perimeter of a square of side 85m = 340m
The perimeter of a rectangle with l = 130 and b = 72m = 404m
Peter covers more disatance by 64m.
Q5. -8y+5
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Q4) Distance covered = perimeter
side of square field = 85m
perimeter of square = 4× side
= 4 × 85 = 340m
Distance covered by Peter = 340m
length of rectangular field = 130m
breadth = 72m
perimeter of rectangular field = 2(length + breadth)
= 2(130 +72)
= 2 × 202 = 404
Distance covered by Bela = 404m
since 404 > 340
404 - 340 = 64m
Bela covered more distance than Peter by 64m
Q5) -8y + 5
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