Question

please answer this question

Answer 1

1/√9-√8

Rationalise the denominator....

1/√9-√8 X √9+√8/√9+√8

√9+√8/ (√9)^2-(√8)^2

√9+√8/9-8

√9+√8/1

√9+√8. Ans....

HOPE IT HELP U

Answer 2

$\frac{1}{ \sqrt{9 } - \sqrt{8} }$
Doing rationalization
$\frac{1}{ \sqrt{9} - \sqrt{8} } \times \frac{ \sqrt{9} + \sqrt{8} }{ \sqrt{9} + \sqrt{8} }$

Using a²-b²=(a-b) (a+b)

$\frac{ \sqrt{9} + \sqrt{8} }{( \sqrt{9})^{2} - (\sqrt{8}) ^{2} }$

$\frac{ \sqrt{9} + \sqrt{8} }{9 - 8}$


$\frac{ \sqrt{9} + \sqrt{8} }{1}$

$\sqrt{9} + \sqrt{8}$

This is ur ans hope it will help you