Question

please answer this question ​

Answer 1

Step-by-step explanation:

Given:-

⇒x=cosecA+cosA

⇒y=cosecA−cosA

To prove:-

⇒( x+y) 2+( 2x−y )2 −1=0

∴x+y=cosecA+cosA+cosecA−cosA=2cosecA

x−y=cosecA+cosA−cosecA+cosA=2cosA

∴( x+y) 2+( 2x−y ) 2−1=( 2 cosec A2)2 +(2cosA )2−1

⇒(sinA) 2+(cosA) 2−1

⇒sin 2 A+cos 2 A−1

⇒1−1

⇒0

Hope it helps you..

pls mark as brainliest

Answer 2

Answer:

#1 ..thanks thanks thanks thanks thanks thanks thanks thanks