Question

please answer this question...​

Answer 1

Answer:

1) PR=PR (common)

PTR=MPR(alternate angles)

TPR=MRP(alt. angles)

therefore, PTR is congruent to RMP

2) RT||PM and equal by CPCT

Answer 2

Answer:

i) In triangle PTR and triangle RMP.

=> angle TPR = angle MPR (Alt.int.angle)

=> PT = MR (given)

=> PR = PR (common side)

So, by S-A-S congruence criteria triangle PTR congruent to triangle RMP (proved)

ii) RT = RM (by C.P.C.T)

=> angle TRP = angle MPR (by C.P.C.T)

hence, RT || PM (because angle TRP and angle MRP are alt.int.angle).