please answer this question
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Answered by
1
Answer:
(sec^2×cot^2)-cot^2=1=)1-cot^2=1
sin^2=1 (sin^2=1-cot^2)
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Answered by
13
Topic
Trigonometry
To Prove
( sec²θ - 1 )cot²θ = 1
Formula
1 + tan²θ = sec²θ
tan²θ = sec²θ - 1
tanθ × cotθ = 1
Solution
Solving LHS,
( sec²θ - 1 )cot²θ
tan²θ × cot²θ
( tanθ × cotθ )²
1²
1
So, LHS = 1.
We observe that LHS = RHS.
Hence, Proved.
More Formulae
sin²θ + cos²θ = 1
1 + cot²θ = cosec²θ
sin2θ = 2sinθcosθ
cos2θ = cos²θ - sin²θ
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