Question

Please answer this question........

Answer 1

Answer:

Step-by-step explanation:

This problem is quite interesting. Since I don't have pen and paper right now, I am telling you the process.

Assume that, you know that ∠BAC = 90°

Now, since AB = AC = a (say)

Using Pythagoras Th,

BC = diameter = √(a² + a²) = √2 a

Hence the area of the circle = π(√2a)² = 2πa²      ................. (1)

Also, using symmetry,

the area of the circle is

2 ( ΔABC + Shaded Region )

= 2 ( a²/2 + 126 ) ........................... (2)

Now equate both (1) and (2), get the value of a [pref. a²] and put into eq (1) for your result.

Good luck

Answer 2

Answer:

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