please answer this question
Answers
Answer:
(a). speed of aeroplane moving in north direction = 1000 km = 1000* 5/18
= 5000/18
1 hour 30 min = 5400 sec
S = D/T
D = S*T
D = 5000/18* 5400
D = 1500000m
= 1500000/1000
D = 1500 Km
hence aeroplane towars north covered 1500km
(b). Speed of aeroplane moving in west direction = 12,000km = 12000* 5/18
= 1000/3 m/s
1 hour 30 mins = 5400 sec
S = D/T
D = S*T
D = 1000/3* 5400
1800000m
D = 1800000/1000
D = 1800km
hence aeroplane traveling in west direction travelled 1800 km
(c). Angle AOB is 90 degree
(d). In triangle AOB
using Pythagoras theorem
along AO = aeroplane moving in north
BO = aeroplane moving in west
(AB)^2 = (AO)^ 2 + (BO)^2
= (1500)^2 + (1800)^2
2250000 +3240000
AB =✓54,90,000
hence correct option is (iii)
(e). The given prb is based on height and distance concept
I hope this answer will help you
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Step-by-step explanation:
1. for converting km/hr into m/s
multiply the given number with 5/18
2. 1 km = 1000m
1m =. 1/1000Km