Question

please answer this question​

Answer 1

Answer:

(a). speed of aeroplane moving in north direction = 1000 km = 1000* 5/18

= 5000/18

1 hour 30 min = 5400 sec

S = D/T

D = S*T

D = 5000/18* 5400

D = 1500000m

= 1500000/1000

D = 1500 Km

hence aeroplane towars north covered 1500km

(b). Speed of aeroplane moving in west direction = 12,000km = 12000* 5/18

= 1000/3 m/s

1 hour 30 mins = 5400 sec

S = D/T

D = S*T

D = 1000/3* 5400

1800000m

D = 1800000/1000

D = 1800km

hence aeroplane traveling in west direction travelled 1800 km

(c). Angle AOB is 90 degree

(d). In triangle AOB

using Pythagoras theorem

along AO = aeroplane moving in north

BO = aeroplane moving in west

(AB)^2 = (AO)^ 2 + (BO)^2

= (1500)^2 + (1800)^2

2250000 +3240000

AB =✓54,90,000

hence correct option is (iii)

(e). The given prb is based on height and distance concept

I hope this answer will help you

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Step-by-step explanation:

1. for converting km/hr into m/s

multiply the given number with 5/18

2. 1 km = 1000m

1m =. 1/1000Km