Question

please answer this question​

Answer 1

Answer:

6

Step-by-step explanation:

On solving the brackets (x^2-9) will be cancelled and then you will have Lt 2x

putting the value of x

2x3=6

Answer 2

$\rm \large \longrightarrow \lim \limits_{ x\rightarrow3}( {x}^{2} - 9) \bigg( \dfrac{1}{x + 3} + \dfrac{1}{x - 3} \bigg) \\ \\ \\ \\ \rm \large \longrightarrow \lim \limits_{ x\rightarrow3}( {x}^{2} - 9) \bigg( \dfrac{x - 3 + x + 3}{(x + 3)(x - 3)} \bigg)\\ \\ \\ \\ \rm \large \longrightarrow \lim \limits_{ x\rightarrow3}( {x}^{2} - 9) \bigg( \dfrac{x - 3 + x + 3}{(x + 3)(x - 3)} \bigg)\\ \\ \\ \\ \rm \large \longrightarrow \lim \limits_{ x\rightarrow3}( {x}^{2} - 9) \bigg( \dfrac{x + x}{ {x}^{2} - {3}^{2} } \bigg)\\ \\ \\ \\ \rm \large \longrightarrow \lim \limits_{ x\rightarrow3}( {x}^{2} - 9) \bigg( \dfrac{2x}{ {x}^{2} - 9 } \bigg)\\ \\ \\ \\ \rm \large \longrightarrow \lim \limits_{ x\rightarrow3}2x\\ \\ \\ \\ \rm \large \longrightarrow 2\lim \limits_{ x\rightarrow3}x\\ \\ \\ \\ \rm \large \longrightarrow 2 \times 3\\ \\ \\ \\ \rm \large \longrightarrow 6$

Answer : 6