Question

please answer this question ​

Answer 1

Answer:

height of tower x=5.1 m

height of pole h=10.38 m

Step-by-step explanation:

Let h is height of flagpole and x=QR is height of the tower

in the ΔAQR

x/9=cot60°=1/√3

x=9/√3 m=3√3

so height of tower x=3*1.73=5.1 m

Now in the ΔPRA

(x+h)/9=cot30° =√3

x+h=9√3

3√3+h=9√3

h=6√3

=6*1.73=10.38 m

Answer 2

ha problem h

unfollow kro