Question

please answer this question ​

Answer 1

Answer:

2.17 is the answer

please give me like

Answer 2

$\sf \Large Solution!!$

Firstly, we will calculate the base radius by the formula:

Area of the base = $\sf \pi r^{2}$

Then we can easily find out the height of the mountain by the formula:

Height = $\sf \sqrt{(Slant\:height)^{2}-(Base\:radius)^{2}}$

Let the height be h.

Let the base radius be r.

Let the slant height be l.

$\sf \to 1.54\:km^{2}=\pi r^{2}$

$\sf \to 1.54\:km^{2}=\dfrac{22}{7}\times r^{2}$

$\sf \to r^{2}=\dfrac{1.54\:km^{2}\times 7}{22}$

$\sf \to r^{2}=0.49\:km^{2}$

$\sf \to r=\sqrt{0.49\:km^{2}}$

$\sf \to r=0.7\:km$

$\sf \large Now,$

$\sf \to h=\sqrt{l^{2}-r^{2}}$

$\sf \to h=\sqrt{(2.5\:km)^{2}-(0.7\:km)^{2}}$

$\sf \to h=\sqrt{6.25\:km^{2}-0.49\:km^{2}}$

$\sf \to h=\sqrt{5.76\:km^{2}}$

$\sf \to h=2.4\:km$

The height of the mountain is 2.4 km.