Question

please answer this question ​

Answer 1

Answer:

Radius of hemisphere = 2.1 cm

Volume of hemisphere = [2/3] πr³

= [2/3] × [22/7] × [2. 1]³

Volume of hemisphere  = 19. 404 cm³

Height of cone = 4 cm

Volume of cone = [1/3] πr²h

= [1/3] × [22/7] × [2. 1]² ×4

= 18. 48 cm³

Volume of the object = 18. 48 +19. 404

= 37. 884 cm³

Volume of cylindrical tub = πr²h

= [22/7] × 5² ×9. 8

= 770 cm³

When the object is immersed in the tub, volume of water equal to the volume of the object is displaced from the tub.

Volume of water left in the tub = 770 -37. 884

= 732. 116 cm³

∴ Volume of the water left in the tub is 732. 116 cm³

Step-by-step explanation:

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Answer 2

⇫ ⇫ ⇫ ⇫ ⇫ ⇫ ⇫ ⇫

$\huge\mathcal\color{red}<u>Solution</u>$

Radius of hemisphere = 2.1 cm

Volume of hemisphere = $\frac{2}{3}$πr³

$\color{blue}↝$ $\frac{2}{3}$ × $\frac{22}{7}$ × [2. 1]³

Volume of hemisphere  = 19. 404 cm³

Height of cone = 4 cm

Volume of cone = $\frac{1}{3}$ πr²h

$\color{orange}↝$\frac{1}{3}[/tex] ×$\frac{22}{7}$ × 2. 1² ×4

$\color{orange}↝$18. 48 cm³

Volume of the object = 18. 48 +19. 404

= 37. 884 cm³

Volume of cylindrical tub = πr²h

$\color{green}↝$$\frac{22}{7}$ × 5² ×9. 8

$\color{green}↝$ 770 cm³

When the object is immersed in the tub, volume of water equal to the volume of the object is displaced from the tub.

Volume of water left in the tub = 770 -37. 884

= 732. 116 cm³

∴ Volume of the water left in the tub is 732. 116 cm³