please answer this question
Attachments:
Answers
Answered by
0
Heya !!!
Her ur answer !!
=>Sol: Let a is any positive integer, and let b = 6
By applying Eulid's Division Lemma,
we get a = bq + r then the r can be 0 , 1, 2, 3, 4, 5.
Possible values of a = 6q, or 6q+ 1 or 6q+ 2 or 6q + 3 or 6q + 4 or 6q + 5
6q, 6q+2, 6q+4 are divisible by 2.
But 6q+1, 6q+3 or 6q+5 are not divisible by 2.
Hence 6q + 1, 6q + 3 and 6q + 5 are the odd positive inteters
Hope this helps you ☺
Her ur answer !!
=>Sol: Let a is any positive integer, and let b = 6
By applying Eulid's Division Lemma,
we get a = bq + r then the r can be 0 , 1, 2, 3, 4, 5.
Possible values of a = 6q, or 6q+ 1 or 6q+ 2 or 6q + 3 or 6q + 4 or 6q + 5
6q, 6q+2, 6q+4 are divisible by 2.
But 6q+1, 6q+3 or 6q+5 are not divisible by 2.
Hence 6q + 1, 6q + 3 and 6q + 5 are the odd positive inteters
Hope this helps you ☺
Answered by
0
Here it is....mark as BRAINLIEST!!!☺......
Attachments:
Similar questions