Question

please answer this question ​

Answer 1

Given :-

• The 1 and -2 are two zeroes of the cubic polynomial.

• The cubic polynomial is x^3 - 4x^2 - 7x + 10

Solution :-

The given cubic polynomial is

x^3 - 4x^2 - 7x + 10

Put the required values of two zeroes that is 1 and -2 in given polynomial

( 1 )^3 + 4 ( -2)^2 - 7x + 10 = 0

1 + 4 * 4 - 7x + 10 = 0

1 + 16 - 7x + 10 = 0

17 - 7x + 10 = 0

27 - 7x = 0

-7x = -27

x = -27/-7

x = 27/7

Lets verify the value of third zero ,

Put the value of all three zeroes in the given polynomial

Therefore,

(1)^3 + 4 * ( - 2)^2 - 7( 27/7) + 10

1 + 4 * 4 - 27 + 10

1 + 16 -27 + 10

17 -27 + 10

-10 + 10 = 0

[ • Cubic polynomials are those polynomials whose highest power of degree is 3 ] $.$

Answer 2

Answer:

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