Question

please answer this question

Answer 1

I think 6 is the answer

Answer 2

$Given : 2^{x-1} + 2^{x+1} = 320$

$2^{x-1} + * 2^{x-1+2} = 320$

$2^{x-1} + 2^2 * 2^{x-1} = 320$

$2^{x-1} (1 + 2^{2} ) = 320$

$2^{x-1} (5) = 320$

$2^{x-1} = \frac{320}{5}$

$2^{x-1} = 64$

$2^{x-1} = 2^6$

x - 1 = 6

x = 1 + 6

x = 7.



Hope this helps!