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Given- AB=DB,AC=DC
find- X and y
solution- In∆ABC and ∆DBC
AB = DB (given)
AC = DC (given)
BC = BC (common)
∆ABC congruent to ∆DBC (by sss congruence condition)
angle ABC =angle DBC (by cpct) __ 1.
angle ACB = angle DCB ( by cpct) __ 2.
y+3=46° (from 1.). 35°= 2x+5 (from 2.)
y=46-3. 35-5 = 2x
y =43°. 30/2 =x
y= 43°. 15° =x
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