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1. side AD = side AD. (common side)
side AB = side AC. (given)
angle DAB = angle DAC. (AD is bisector of angle BAC)
2. yes ∆ADB = ∆ ADC
Reason (SAS test of congruence)
3. angle B = angle C.
Reason (corresponding angle of congruent triangle)
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1.) State three pairs of equal parts :-
➙ AB = AC
➙ AD = AD
➙ ∠ BAD = ∠ CAD
2.) Is ∆ ADB ≅ ∆ ADC ? Give reasons .
In ∆ ADB & ∆ ADC
AB = AC ( Given )
∠ BAD = ∠ CAD ( AD is bisector of ∠ BAC )
AD = AD ( Common )
∴ ∆ ADB ≅ ∆ ADC ( By SAS congruency rule )
3.) Is ∠B = ∠C ? Give reasons .
Since, we have proved that ∆ ADB ≅ ∆ ADC.
From the above proof we can conclude that :-
∠B = ∠C ( By Cpct ) ( Cpct :- corresponding parts of congurent triangles .
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