Question

.please answer this question​​

Answer 1

Solution:

It's given that,

→ (a + b)² + (a - b)² = y(a² + b²)

We have to find out the value of y. To do this, we have to simplify the expression.

So,

→ (a + b)² + (a - b)² = y(a² + b²)

→ a² + 2ab + b² + a² - 2ab + b² = y(a² + b²)

→ 2a² + 2b² = y(a² + b²)

→ 2(a² + b²) = y(a² + b²)

Cancelling out a² + b² from both sides, we get,

→ y = 2

★ So, the value of y is 2 (Option B)

Answer:

• y = 2.

•••♪

Answer 2

Answer:

Given:-

${(a + b)}^{2} + {(a - b)}^{2} = y( {a}^{2} + {b}^{2} )$

Identity:-

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

${(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2}$

Solution:-

${a}^{2} + 2ab + {b}^{2} + {a}^{2} - 2ab + {b}^{2} = y( {a}^{2} + {b)}^{2}$

${2a}^{2} + 2 {b}^{2} = y( {a}^{2} + {b}^{2} )$

$2( {a}^{2} + {b}^{2} ) = y( {a}^{2} + {b}^{2})$

${a}^{2} + {b}^{2} \: \: got \: \: cancelled$

y=2

Hence,

The given solution:-

y=2

Option B (2) is correct.