Question

please answer this question​

Answer 1

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☯︎ $\frac{2x-1}{3}$ + 1 = $\frac{x-2}{3}$ + 2

☯︎ $\frac{2x-1+3}{3}$ = $\frac{x-2+6}{3}$

☯︎ $\frac{2x+2}{3}$ = $\frac{x+4}{3}$

☯︎ 3 ( 2x + 2 ) = 3 ( x + 4 )

☯︎ 2x + 2 = x + 4

☯︎ 2x - x = 4 - 2

☯︎ x = 2

Answer 2

Answer:

∙ANSWER∙

☯︎ \frac{2x-1}{3}

3

2x−1

+ 1 = \frac{x-2}{3}

3

x−2

+ 2

☯︎ \frac{2x-1+3}{3}

3

2x−1+3

= \frac{x-2+6}{3}

3

x−2+6

☯︎ \frac{2x+2}{3}

3

2x+2

= \frac{x+4}{3}

3

x+4

☯︎ 3 ( 2x + 2 ) = 3 ( x + 4 )

☯︎ 2x + 2 = x + 4

☯︎ 2x - x = 4 - 2

☯︎ x = 2