Question

PLEASE ANSWER THIS QUESTION !!
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Answer 1

Answer:

Rs.16,500,000

Step-by-step explanation:

Refer figure,

In △ABC

a=122m,b=22m,c=120m

s=2a+b+c=2122+22+120

=132m

ar△ABC=s(s−a)(s−b)(s−c)=132(132−122)(132−23)(132−120)

=132×10×110×12=132×10×11×10×12=(132)2×(10)2

=132×10=1320 m2

Rent of 1 m2 per year = Rs. 5000

Rent of 1 m2 per month = Rs.125000

Rent of 1 m2 for 3 months=Rs.123×5000

Rent of 1320 m2 for 3 months=Rs. (12

Answer 2

$\sf The\: length\: of\: the \:sides\: of\: the \:triangular\: walls \:are\: 122 \:m, \:22\:m\: and \:120\:m.$

$\sf \: First \: of \: all \: we \: have \: to \: find \: the \: simi-perimeter.$

$\sf \: Semi - perimeter = \dfrac{First \: side + Second \: side + Third \: side}{2}$

$\sf \implies \: \dfrac{122 + 22 + 120}{2}$

$\sf \implies \: \dfrac{264}{2} = 132$

$\underline{ \sf \: So, \: semi-perimeter = 132 \: metre}$

$\bf \: Now,$

$\sf \: Area \: of \: one \: triangular \: wall \: by \: using \: Heron's \: formula.$

$\sf \implies \: \sqrt{S(S -First \: side ) (S - Second \: side)(S - Third \: side)}$

$\sf \: Putting \: the \: values,$

$\sf \implies \: \sqrt{132(132 -122 ) (132 - 22)(132 - 120)}$

$\sf \implies \: \sqrt{132 \times 10 \times 110 \times 12}$

$\sf \implies \: 1320 \: m^{2}$

$\sf \: Now, Yearly \: rent = Rs. 5000 \: per \: m ^{2}$

$\sf \: Therefore, monthly \: rent = Rs. \: 5000 \times \dfrac{1}{12} \: per \: m ^{2}$

$\sf \: Company \: hired \: one \: of \: its \: wall \: for \: 3 \: month.$

$\sf \: Thus, rent \: payed \: after \: 3 \: months :$

$\sf \implies \: Rs. \: 1320 \times \dfrac{5000}{12} \times 3$

$\sf \implies \:110 \times \dfrac{5000}{1} \times 3$

$\sf \implies \:110 \times 5000 \times 3$

$\sf \implies \: Rs. \: 1650000$

$\underline{ \boxed{ \pink{\sf \: Hence, our \: answer \: is \: Rs. \: 1650000}}}$