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QUESTION: The sum of two numbers is 99. If one number is 20% more than the other, find the two numbers.
SOLUTION: Two numbers are 54 and 45
GIVEN:
- sum of two number is 99.
- one number is 20% more that other.
EXPLANATION:
- Let first number be x
- second number will 99 - x
Now, According to the question,
=> x = 99 - x + 20/100(99 - x)
=> x = 99 - x + 19.8 + 0.2x
=> 2.2x = 118.8
=> x = 118.8/2.2 = 54
Other number will be 99 - x = 99 - 54 = 45
Hence, the two numbers are 54 and 45
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