Question

please answer this question​

Answer 1

Answer:

answer is option b please mark me as brainliest

Answer 2

$\huge\mathtt\purple{SOLUTION:-}$

$\mathtt{ 1) 2xy \times ( - 4xy) \times 6 {xy}^{2} }$

$\mathtt{ = - 48 {x}^{4} {y}^{4} }$

$\mathtt{ 2) abc \times( 3ab - 5bc)}$

$\mathtt{ = 3 {a}^{2} {b}^{2} c - 5a {b}^{2} {c}^{2} }$

$\mathtt{ 3)(4x + 3y)(2x + 3y)}$

$\mathtt{ = 4x(2x + 3y) + 3y(2x + 3y)}$

$\mathtt{ = {6x}^{2} + 12xy + 6xy + {9y}^{2} }$

$\mathtt{ = {6x}^{2} + 18xy + {9y}^{2} }$

i - r, ii - p, iii - q

$\fbox\purple{Option b is correct}$