Question

Please answer this question ​

Answer 1

Answer:

$\sin( \alpha ) = \sqrt{3} \div 2 \\ \alpha = 60 \\ \csc(60) + \cot(60) = 1 \div \sin(60) + 1 \div \tan(60) \\ = 2 \div \sqrt{3} \: \: + 1 \div \sqrt{3} \\ = (2 + 1) \div \sqrt{3} \\ = 3 \div \sqrt{3 } = \sqrt{3}$