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Answers
Answer:
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Answer:
14
Step-by-step explanation:
How to solve your problem
4
+
1
2
=
4
\frac{x}{4}+\frac{1}{2}=4
4x+21=4
Solve
1
Find common denominator
4
+
1
2
=
4
\frac{x}{4}+\frac{1}{2}=4
4x+21=4
4
+
4
⋅
1
2
4
=
4
\frac{x}{4}+\frac{4 \cdot \frac{1}{2}}{4}=4
4x+44⋅21=4
2
Combine fractions with common denominator
4
+
4
⋅
1
2
4
=
4
\frac{x}{4}+\frac{4 \cdot \frac{1}{2}}{4}=4
4x+44⋅21=4
+
4
⋅
1
2
4
=
4
\frac{x+4 \cdot \frac{1}{2}}{4}=4
4x+4⋅21=4
3
Multiply the numbers
+
4
⋅
1
2
4
=
4
\frac{x+{\color{#c92786}{4}} \cdot {\color{#c92786}{\frac{1}{2}}}}{4}=4
4x+4⋅21=4
+
2
4
=
4
\frac{x+{\color{#c92786}{2}}}{4}=4
4x+2=4
4
Multiply all terms by the same value to eliminate fraction denominators
+
2
4
=
4
\frac{x+2}{4}=4
4x+2=4
4
(
+
2
4
)
=
4
⋅
4
4(\frac{x+2}{4})=4 \cdot 4
4(4x+2)=4⋅4
5
Cancel multiplied terms that are in the denominator
4
(
+
2
4
)
=
4
⋅
4
4(\frac{x+2}{4})=4 \cdot 4
4(4x+2)=4⋅4
+
2
=
4
⋅
4
x+2=4 \cdot 4
x+2=4⋅4
6
Multiply the numbers
+
2
=
4
⋅
4
x+2={\color{#c92786}{4}} \cdot {\color{#c92786}{4}}
x+2=4⋅4
+
2
=
1
6
x+2={\color{#c92786}{16}}
x+2=16
7
Subtract
2
2
2
from both sides of the equation
+
2
=
1
6
x+2=16
x+2=16
+
2
−
2
=
1
6
−
2
x+2{\color{#c92786}{-2}}=16{\color{#c92786}{-2}}
x+2−2=16−2
8
Simplify
Subtract the numbers
Subtract the numbers
=
1
4